Multiply both sides by $x$.
$$2x=5+{3\over x}$$
$$2x\times x=5\times x+{3\over x}\times x$$
$$2x^2=5x+3$$
$$2x^2-5x-3=0$$
$$2x^2-6x+1x-3=0$$
$$2x(x-3) + 1(x-3)=0$$
$$(2x+1)(x-3)=0$$
$$\therefore x=-0.5, 3$$
JH2015 :-)
This blog dates back to 2015-16 while I was teaching senior high school Advanced Mathematics (formerly 2U Maths) in Sydney, Australia. It contains a wide range of explanations, notes, and resources covering senior secondary-level mathematics topics. The easiest ways to navigate are by using the search bar or browsing through the labels/tags. If you find my content helpful and would like to support my work, a coffee donation is greatly appreciated — thank you!
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