This blog dates back to 2015-16 while I was teaching senior high school Advanced Mathematics (formerly 2U Maths) in Sydney, Australia. It contains a wide range of explanations, notes, and resources covering senior secondary-level mathematics topics. The easiest ways to navigate are by using the search bar or browsing through the labels/tags. If you find my content helpful and would like to support my work, a coffee donation is greatly appreciated — thank you!
Tuesday, 24 May 2016
Question 6 pls Trigonometric Functions
SOLUTION
Put $\sin x =\cos x$ to find where the two curves intersect..
Divide both sides by $\cos x$ to get $\tan x=1$ and this gives solution $x=\pi/4$.
When $x=\pi/4$, $y=\sin \pi/4 = 1/\sqrt{2}$ as required.
JH
Labels:
Trigonometric Functions
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